Change in graph number [SOLVED]

[Diztly Wardizt]

Hallo Fernando,

I have trouble changing the chart sequence number, please help, how to calculate this math, I tried it was not good.

this is the code that I use

Code: Select all

void LedgrphScreen()//------------------------------------------------------------ tela =61
{
  int x, y, z, grafico;
  int16_t n;
  char buf[8];
  float temperatura;
  int j = 0;
  int i = 0;
  int k = 0;
  float soma = 0.0f; // Soma dos valores de todos os elementos
  float media = 0.0f; // Média dos valores
  float linhaR;
  int f = 30;

  strcpy_P(buffer, (char*)pgm_read_word_near(&(tabela_textos[51])));
  printHeader("TEMP.LED GRAPHIC"); // "TEMP.WATER GRAPHIC"; // tabela_textos[51]

  setFont(SMALL, 255, 255, 255, 0, 0, 0);
  myGLCD.print("TEMP. LED NOW :", 5, 220);

  for (float i = 47; i > 25.0; i -= 2)
  {
    myGLCD.printNumF(i, 1, 5, 3 + f);

    f += 15;
  }

  f = 255;
  for (int i = 22; i > 0; i -= 2)
  {
    myGLCD.printNumI(i, f, 193);
    f -= 20;
  }

  myGLCD.print("0", 275, 193);
  myGLCD.drawCircle(15, 21, 2);
  myGLCD.print("C", 20, 18);
  myGLCD.print("H", 290, 193);
  myGLCD.drawLine(40, 30, 40, 190); // Eixo y
  myGLCD.drawLine(40, 190, 290, 190);  // Eixo x
  myGLCD.setColor(64, 64, 64);  // Malha

  //EIXO X
  for (int k = 30; k < 190; k += 7)
  {
    myGLCD.drawLine(40, k, 290, k);
  }

  //EIXO Y
  for (int l = 60; l < 300; l += 20)
  {
    myGLCD.drawLine(l, 30, l, 190);
  }

  linhaR = tempH;  //  Linhas de comparação

  if ((linhaR >= 27) && (linhaR <= 47))
  {
    x = (190 - ((linhaR - 27) * 10));
  }
  else if (linhaR > 47)
  {
    x = 30;
  }
  else if (linhaR < 27)
  {
    x = 190;
  }


  myGLCD.setColor(255, 0, 0);
  myGLCD.drawLine(40, x, 290, x);// Temperatura desejada

  strcpy_P(buffer, (char*)pgm_read_word_near(&(tabela_textos[11])));
  printButton(buffer, iniC[0], iniC[1], iniC[2], iniC[3], false, 4);

  strcpy_P(buffer, (char*)pgm_read_word_near(&(tabela_textos[1])));
  printButton(buffer, menU[0], menU[1], menU[2], menU[3]);

  strcpy_P(buffer, (char*)pgm_read_word_near(&(tabela_textos[66])));
  printButton(buffer, prOK[0], prOK[1], prOK[2], prOK[3]);

  setFont(SMALL, 255, 255, 0, 0, 0, 0);
  myGLCD.printNumF(tempH, 2, 135, 220);  // LED

  int d = 41 + (NumMins(t.hour, t.min) / 6);

  myGLCD.drawLine(d, 30, d, 190); // Linha de marcação do horário.
  myGLCD.print(rtc.getTimeStr(FORMAT_SHORT), d + 2, 75, 270);

  selecionar_SPI(SD_CARD);

  if (file.open("LOGTLED.TXT", O_READ))
  {
    while ((n = file.read(buf, sizeof(buf))) > 0)
    {
      temperatura = atof(buf);
      soma += temperatura;

      if (strlen(buf) == 5)
      {
        i++;
        k++;
      }

      if (temperatura <= 2 )
      {
        k -= 1;
      }

      if (i == 6)
      {
        media = soma / k;
        i = 0;
        j++;
        soma = 0;
        k = 0;

        if ((media) > 47)
        {
          grafico = 30;
        }
        else if ((media >= 27) && (media <= 47))
        {
          grafico = (190 - ((media - 27) * 10));
        }
        else
        {
          grafico = 190;
        }
        setFont(SMALL, 204, 32, 255, 0, 0, 0);

        if (j < 250)
        {
          myGLCD.drawPixel((40 + j), grafico);
          myGLCD.drawPixel((40 + j), (1 + grafico));
          myGLCD.drawPixel((41 + j), grafico);
          myGLCD.drawPixel((41 + j), (1 + grafico));
        }
      }
    }
    file.close();
  }
}

result images this code


thanks

[Fernando Garcia]

Hi!

Happy to know you are trying learning coding yet.

I don't think good idea make one line per degress in grid lines.

I think it should be:

Code: Select all

  // EIXO X
  for (int k = 40; k < 180; k += 15)
  {
    myGLCD.drawLine(40, k, 290, k);
  }

For others line you have to adjust basically this equation.

Code: Select all

  if ((linhaR >= 27) && (linhaR <= 47))
  {
    x = (190 - ((linhaR - 27) * 10));
  }

or

Code: Select all

  if ((linhaR >= 27) && (linhaR <= 47))
  {
    x = (190 - ((linhaR - 27) * multiplier));
  }

x here is the y coordinate for red line. So you have to think what should be the multiplier to make x be 40 when linhaR is 47 or make x be 190 when linhaR is 27.

So you can make for linhaR = 47:

Code: Select all

40 = (190 - (47 - 27) * multiplier)
40 = 190 - 20 multiplier
20 multiplier = 190 - 40
multiplier = 150 / 20
multiplier = 7.5

Just to make sure when linhaR is 47 x should be 40:

Code: Select all

x = 190 - (47 -27) * 7.5
x = 190 - 20 * 7.5
x = 190 - 150
x = 40

Therefore the equation is:

Code: Select all

x = (190 - ((linhaR - 27) * 7.5));

Let me know if it help you.

Best regards.

[Diztly Wardizt]

Thank you answered quickly and detailed explanation,
I am really happy for this.

thank you I will try, I will post the results here


thanks.

[Fernando Garcia]

Hi!

The problem was solved?

Best regards.

[Diztly Wardizt]

Fernando Garcia » Yesterday 2:22 am wrote:

Hi!

The problem was solved?

Best regards.

sorry I haven't tried, this month I'm out of town, maybe next week I can try.

thank you

[Diztly Wardizt]

thank you, this went perfectly, as I expected
This problem solved.

Thanks